\(\sqrt{13+\sqrt{42}}\) का वर्ग किसके बराबर है?
What is the square of \(\sqrt{13+\sqrt{42}}\) equal to?
Explanation opens after your attempt
Correct Answer
D. \(13+\sqrt{42}\)
Concept
The square of a square root gives the number inside. So (\left\(\sqrt{13+\sqrt{42}}\right\)2=13+\sqrt{42}).
Why this answer is correct
The correct answer is D. \(13+\sqrt{42}\). The square of a square root gives the number inside. So (\left\(\sqrt{13+\sqrt{42}}\right\)2=13+\sqrt{42}).
Exam Tip
वर्गमूल का वर्ग अंदर की संख्या देता है। इसलिए (\left\(\sqrt{13+\sqrt{42}}\right\)2=13+\sqrt{42}) है।
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