वर्गमूल सर्पिल में \( \sqrt{50} \) की दूरी का सरलीकृत रूप क्या होगा?
What is the simplified form of the distance \( \sqrt{50} \) in the square root spiral?
Explanation opens after your attempt
Correct Answer
A. \(5\sqrt{2}\)
Concept
\( \sqrt{50}=\sqrt{25\times 2}=5\sqrt{2} \). Extract the largest perfect square while simplifying.
Why this answer is correct
The correct answer is A. \(5\sqrt{2}\). \( \sqrt{50}=\sqrt{25\times 2}=5\sqrt{2} \). Extract the largest perfect square while simplifying.
Exam Tip
\( \sqrt{50}=\sqrt{25\times 2}=5\sqrt{2} \) है। सरलीकरण में सबसे बड़ा पूर्ण वर्ग निकालें।
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