\(\sqrt{539}-\sqrt{275}+\sqrt{99}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{539}-\sqrt{275}+\sqrt{99}\)?
Explanation opens after your attempt
B. \(7\sqrt{11}\)
Concept
\(\sqrt{539}=7\sqrt{11}\), \(\sqrt{275}=5\sqrt{11}\), and \(\sqrt{99}=3\sqrt{11}\). So the result is \(7\sqrt{11}-5\sqrt{11}+3\sqrt{11}=5\sqrt{11}\).
Why this answer is correct
The correct answer is B. \(7\sqrt{11}\). \(\sqrt{539}=7\sqrt{11}\), \(\sqrt{275}=5\sqrt{11}\), and \(\sqrt{99}=3\sqrt{11}\). So the result is \(7\sqrt{11}-5\sqrt{11}+3\sqrt{11}=5\sqrt{11}\).
Exam Tip
\(\sqrt{539}=7\sqrt{11}\), \(\sqrt{275}=5\sqrt{11}\) और \(\sqrt{99}=3\sqrt{11}\) है। इसलिए परिणाम \(5\sqrt{11}\) नहीं, \(7\sqrt{11}-5\sqrt{11}+3\sqrt{11}=5\sqrt{11}\) है।
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