\(\sqrt{432}-\sqrt{192}+\sqrt{48}\) का सरल रूप क्या है?
What is the simplified form of \(\sqrt{432}-\sqrt{192}+\sqrt{48}\)?
Explanation opens after your attempt
Correct Answer
A. \(8\sqrt{3}\)
Concept
\(\sqrt{432}=12\sqrt{3}\), \(\sqrt{192}=8\sqrt{3}\), and \(\sqrt{48}=4\sqrt{3}\). Therefore the result is \(8\sqrt{3}\).
Why this answer is correct
The correct answer is A. \(8\sqrt{3}\). \(\sqrt{432}=12\sqrt{3}\), \(\sqrt{192}=8\sqrt{3}\), and \(\sqrt{48}=4\sqrt{3}\). Therefore the result is \(8\sqrt{3}\).
Exam Tip
\(\sqrt{432}=12\sqrt{3}\), \(\sqrt{192}=8\sqrt{3}\) और \(\sqrt{48}=4\sqrt{3}\) है। इसलिए परिणाम \(8\sqrt{3}\) है।
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