\(\frac{\sqrt{5}+2}{\sqrt{5}-2}\) का सरल रूप क्या है?

What is the simplified form of \(\frac{\sqrt{5}+2}{\sqrt{5}-2}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(9+4\sqrt{5}\)

Step 1

Concept

The conjugate of the denominator is \(\sqrt{5}+2\) and the denominator becomes (1). So the value is (\(\sqrt{5}+2\)2=9+4\sqrt{5}).

Step 2

Why this answer is correct

The correct answer is A. \(9+4\sqrt{5}\). The conjugate of the denominator is \(\sqrt{5}+2\) and the denominator becomes (1). So the value is (\(\sqrt{5}+2\)2=9+4\sqrt{5}).

Step 3

Exam Tip

हर का संयुग्मी \(\sqrt{5}+2\) है और हर (1) बनता है। इसलिए मान (\(\sqrt{5}+2\)2=9+4\sqrt{5}) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

\(\frac{\sqrt{5}+2}{\sqrt{5}-2}\) का सरल रूप क्या है? / What is the simplified form of \(\frac{\sqrt{5}+2}{\sqrt{5}-2}\)?

Correct Answer: A. \(9+4\sqrt{5}\). Explanation: हर का संयुग्मी \(\sqrt{5}+2\) है और हर (1) बनता है। इसलिए मान (\(\sqrt{5}+2\)2=9+4\sqrt{5}) है। / The conjugate of the denominator is \(\sqrt{5}+2\) and the denominator becomes (1). So the value is (\(\sqrt{5}+2\)2=9+4\sqrt{5}).

Which concept should I revise for this Mathematics MCQ?

The conjugate of the denominator is \(\sqrt{5}+2\) and the denominator becomes (1). So the value is (\(\sqrt{5}+2\)2=9+4\sqrt{5}).

What exam hint can help solve this Mathematics question?

हर का संयुग्मी \(\sqrt{5}+2\) है और हर (1) बनता है। इसलिए मान (\(\sqrt{5}+2\)2=9+4\sqrt{5}) है।