\(\frac{8}{\sqrt{27}-\sqrt{11}}\) का परिमेयकृत रूप क्या है?
What is the rationalised form of \(\frac{8}{\sqrt{27}-\sqrt{11}}\)?
Explanation opens after your attempt
Correct Answer
C. (\frac{8\(\sqrt{27}+\sqrt{11}\)}{16})
Concept
Multiplying by the conjugate makes the denominator (27-11=16). So the form is (\frac{8\(\sqrt{27}+\sqrt{11}\)}{16}).
Why this answer is correct
The correct answer is C. (\frac{8\(\sqrt{27}+\sqrt{11}\)}{16}). Multiplying by the conjugate makes the denominator (27-11=16). So the form is (\frac{8\(\sqrt{27}+\sqrt{11}\)}{16}).
Exam Tip
संयुग्मी से गुणा करने पर हर (27-11=16) बनता है। इसलिए रूप (\frac{8\(\sqrt{27}+\sqrt{11}\)}{16}) है।
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