\(\frac{5}{\sqrt{29}+2}\) का परिमेयकृत रूप क्या है?

What is the rationalised form of \(\frac{5}{\sqrt{29}+2}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(\frac{\sqrt{29}-2}{5}\)

Step 1

Concept

Multiplying by the conjugate makes the denominator (29-4=25). So the form is \(\frac{\sqrt{29}-2}{5}\).

Step 2

Why this answer is correct

The correct answer is B. \(\frac{\sqrt{29}-2}{5}\). Multiplying by the conjugate makes the denominator (29-4=25). So the form is \(\frac{\sqrt{29}-2}{5}\).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (29-4=25) बनता है। इसलिए रूप \(\frac{\sqrt{29}-2}{5}\) है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{5}{\sqrt{29}+2}\) का परिमेयकृत रूप क्या है? / What is the rationalised form of \(\frac{5}{\sqrt{29}+2}\)?

Correct Answer: B. \(\frac{\sqrt{29}-2}{5}\). Explanation: संयुग्मी से गुणा करने पर हर (29-4=25) बनता है। इसलिए रूप \(\frac{\sqrt{29}-2}{5}\) है। / Multiplying by the conjugate makes the denominator (29-4=25). So the form is \(\frac{\sqrt{29}-2}{5}\).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate makes the denominator (29-4=25). So the form is \(\frac{\sqrt{29}-2}{5}\).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (29-4=25) बनता है। इसलिए रूप \(\frac{\sqrt{29}-2}{5}\) है।