\( \frac{5}{\sqrt{13}-\sqrt{8}} \) का परिमेय हर वाला रूप क्या है?

What is the rationalised form of \( \frac{5}{\sqrt{13}-\sqrt{8}} \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \( \sqrt{13}+\sqrt{8} \)

Step 1

Concept

Multiplying by the conjugate gives denominator (13-8=5). The numerator also has (5), so the answer is \( \sqrt{13}+\sqrt{8} \).

Step 2

Why this answer is correct

The correct answer is A. \( \sqrt{13}+\sqrt{8} \). Multiplying by the conjugate gives denominator (13-8=5). The numerator also has (5), so the answer is \( \sqrt{13}+\sqrt{8} \).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (13-8=5) आता है। अंश में भी (5) है इसलिए उत्तर \( \sqrt{13}+\sqrt{8} \) है।

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Mathematics Answer, Explanation and Revision Hints

\( \frac{5}{\sqrt{13}-\sqrt{8}} \) का परिमेय हर वाला रूप क्या है? / What is the rationalised form of \( \frac{5}{\sqrt{13}-\sqrt{8}} \)?

Correct Answer: A. \( \sqrt{13}+\sqrt{8} \). Explanation: संयुग्मी से गुणा करने पर हर (13-8=5) आता है। अंश में भी (5) है इसलिए उत्तर \( \sqrt{13}+\sqrt{8} \) है। / Multiplying by the conjugate gives denominator (13-8=5). The numerator also has (5), so the answer is \( \sqrt{13}+\sqrt{8} \).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate gives denominator (13-8=5). The numerator also has (5), so the answer is \( \sqrt{13}+\sqrt{8} \).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (13-8=5) आता है। अंश में भी (5) है इसलिए उत्तर \( \sqrt{13}+\sqrt{8} \) है।