\(\frac{4}{\sqrt{13}-\sqrt{5}}\) का परिमेयकृत रूप क्या है?

What is the rationalised form of \(\frac{4}{\sqrt{13}-\sqrt{5}}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(\frac{\sqrt{13}+\sqrt{5}}{2}\)

Step 1

Concept

Multiplying by the conjugate makes the denominator (13-5=8). So (\frac{4\(\sqrt{13}+\sqrt{5}\)}{8}=\frac{\sqrt{13}+\sqrt{5}}{2}).

Step 2

Why this answer is correct

The correct answer is B. \(\frac{\sqrt{13}+\sqrt{5}}{2}\). Multiplying by the conjugate makes the denominator (13-5=8). So (\frac{4\(\sqrt{13}+\sqrt{5}\)}{8}=\frac{\sqrt{13}+\sqrt{5}}{2}).

Step 3

Exam Tip

संयुग्मी से गुणा करने पर हर (13-5=8) बनता है। इसलिए (\frac{4\(\sqrt{13}+\sqrt{5}\)}{8}=\frac{\sqrt{13}+\sqrt{5}}{2}) है।

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Mathematics Answer, Explanation and Revision Hints

\(\frac{4}{\sqrt{13}-\sqrt{5}}\) का परिमेयकृत रूप क्या है? / What is the rationalised form of \(\frac{4}{\sqrt{13}-\sqrt{5}}\)?

Correct Answer: B. \(\frac{\sqrt{13}+\sqrt{5}}{2}\). Explanation: संयुग्मी से गुणा करने पर हर (13-5=8) बनता है। इसलिए (\frac{4\(\sqrt{13}+\sqrt{5}\)}{8}=\frac{\sqrt{13}+\sqrt{5}}{2}) है। / Multiplying by the conjugate makes the denominator (13-5=8). So (\frac{4\(\sqrt{13}+\sqrt{5}\)}{8}=\frac{\sqrt{13}+\sqrt{5}}{2}).

Which concept should I revise for this Mathematics MCQ?

Multiplying by the conjugate makes the denominator (13-5=8). So (\frac{4\(\sqrt{13}+\sqrt{5}\)}{8}=\frac{\sqrt{13}+\sqrt{5}}{2}).

What exam hint can help solve this Mathematics question?

संयुग्मी से गुणा करने पर हर (13-5=8) बनता है। इसलिए (\frac{4\(\sqrt{13}+\sqrt{5}\)}{8}=\frac{\sqrt{13}+\sqrt{5}}{2}) है।