\(\frac{3}{\sqrt{14}+\sqrt{5}}\) का परिमेयकृत रूप क्या है?
What is the rationalised form of \(\frac{3}{\sqrt{14}+\sqrt{5}}\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{\sqrt{14}-\sqrt{5}}{3}\)
Concept
Multiplying by the conjugate makes the denominator (14-5=9). So (\frac{3\(\sqrt{14}-\sqrt{5}\)}{9}=\frac{\sqrt{14}-\sqrt{5}}{3}).
Why this answer is correct
The correct answer is A. \(\frac{\sqrt{14}-\sqrt{5}}{3}\). Multiplying by the conjugate makes the denominator (14-5=9). So (\frac{3\(\sqrt{14}-\sqrt{5}\)}{9}=\frac{\sqrt{14}-\sqrt{5}}{3}).
Exam Tip
संयुग्मी से गुणा करने पर हर (14-5=9) बनता है। इसलिए (\frac{3\(\sqrt{14}-\sqrt{5}\)}{9}=\frac{\sqrt{14}-\sqrt{5}}{3}) है।
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