अनुक्रम \(1,6,13,22,\ldots\) का सामान्य पद क्या है?

What is the general term of the sequence \(1,6,13,22,\ldots\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(a_n=n^2+2n-2\)

Step 1

Concept

\(n^2+2n-2\) gives (1,6,13,22). In exams test a quadratic rule on the first four terms.

Step 2

Why this answer is correct

The correct answer is A. \(a_n=n^2+2n-2\). \(n^2+2n-2\) gives (1,6,13,22). In exams test a quadratic rule on the first four terms.

Step 3

Exam Tip

\(n^2+2n-2\) से (1,6,13,22) मिलते हैं। परीक्षा में वर्गीय नियम को पहले चार पदों पर जाँचें।

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Mathematics Answer, Explanation and Revision Hints

अनुक्रम \(1,6,13,22,\ldots\) का सामान्य पद क्या है? / What is the general term of the sequence \(1,6,13,22,\ldots\)?

Correct Answer: A. \(a_n=n^2+2n-2\). Explanation: \(n^2+2n-2\) से (1,6,13,22) मिलते हैं। परीक्षा में वर्गीय नियम को पहले चार पदों पर जाँचें। / \(n^2+2n-2\) gives (1,6,13,22). In exams test a quadratic rule on the first four terms.

Which concept should I revise for this Mathematics MCQ?

\(n^2+2n-2\) gives (1,6,13,22). In exams test a quadratic rule on the first four terms.

What exam hint can help solve this Mathematics question?

\(n^2+2n-2\) से (1,6,13,22) मिलते हैं। परीक्षा में वर्गीय नियम को पहले चार पदों पर जाँचें।