( \(4\sqrt{3}+3\sqrt{2}\)2 ) का विस्तार क्या है?

What is the expansion of ( \(4\sqrt{3}+3\sqrt{2}\)2 )?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(66+24\sqrt{6}\)

Step 1

Concept

The first square is (48) and the second square is (18). The middle term is \(2\times4\sqrt{3}\times3\sqrt{2}=24\sqrt{6}\).

Step 2

Why this answer is correct

The correct answer is A. \(66+24\sqrt{6}\). The first square is (48) and the second square is (18). The middle term is \(2\times4\sqrt{3}\times3\sqrt{2}=24\sqrt{6}\).

Step 3

Exam Tip

पहला वर्ग (48) और दूसरा वर्ग (18) है। मध्य पद \(2\times4\sqrt{3}\times3\sqrt{2}=24\sqrt{6}\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

( \(4\sqrt{3}+3\sqrt{2}\)2 ) का विस्तार क्या है? / What is the expansion of ( \(4\sqrt{3}+3\sqrt{2}\)2 )?

Correct Answer: A. \(66+24\sqrt{6}\). Explanation: पहला वर्ग (48) और दूसरा वर्ग (18) है। मध्य पद \(2\times4\sqrt{3}\times3\sqrt{2}=24\sqrt{6}\) है। / The first square is (48) and the second square is (18). The middle term is \(2\times4\sqrt{3}\times3\sqrt{2}=24\sqrt{6}\).

Which concept should I revise for this Mathematics MCQ?

The first square is (48) and the second square is (18). The middle term is \(2\times4\sqrt{3}\times3\sqrt{2}=24\sqrt{6}\).

What exam hint can help solve this Mathematics question?

पहला वर्ग (48) और दूसरा वर्ग (18) है। मध्य पद \(2\times4\sqrt{3}\times3\sqrt{2}=24\sqrt{6}\) है।