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What is the ascending order of (9.009), (9.0909), (9.0099), and (9.900)?

Answer and explanation

Correct answer: \(9.009<9.0099<9.0909<9.900\)

Write all the numbers up to four decimal places for comparison: \(9.0090, 9.0099, 9.0909, 9.9000\). Comparing the digits after the decimal from left to right gives \(9.0090<9.0099<9.0909<9.9000\). Therefore, option A is correct. Option D incorrectly places \(9.0909\) before \(9.0099\). Exam tip: Add zeros at the end, when needed, to make the decimal places equal before comparing decimals.

Related tags

Number SystemsDecimal RepresentationComparing DecimalsAscending OrderClass 9 MathematicsMathematicsClass 9 Mcq

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