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What is the ascending order of (8.008), (8.0808), (8.0088), and (8.800)?

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Answer and explanation

Correct answer: \(8.008<8.0088<8.0808<8.800\)

Write all numbers up to four decimal places: \(8.0080, 8.0808, 8.0088, 8.8000\). The first decimal digits are \(0,0,0,8\), so \(8.8000\) is the greatest. Among the remaining numbers, \(8.0080<8.0088<8.0808\). Hence, the ascending order is \(8.008<8.0088<8.0808<8.800\). Option D incorrectly places \(8.0808\) before \(8.0088\). Exam tip: append trailing zeros to make the decimal places equal before comparing decimals.

Related tags

Number SystemsDecimal RepresentationAscending OrderComparing DecimalsClass 9 Mathematics

Frequently asked questions

What is the correct answer to this question?

\(8.008<8.0088<8.0808<8.800\)

Why is this the correct answer?

Write all numbers up to four decimal places: \(8.0080, 8.0808, 8.0088, 8.8000\). The first decimal digits are \(0,0,0,8\), so \(8.8000\) is the greatest. Among the remaining numbers, \(8.0080<8.0088<8.0808\). Hence, the ascending order is \(8.008<8.0088<8.0808<8.800\). Option D incorrectly places \(8.0808\) before \(8.0088\). Exam tip: append trailing zeros to make the decimal places equal before comparing decimals.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Number Systems. Topic: Decimal representation.

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