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Class 9MathematicsExploring Algebraic IdentitiesFactorisationMediumLevel 71
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Using grouping, what is the factorised form of (ax+ay+bx+by)?

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Answer and explanation

Correct answer: ((a+b)(x+y))

First it becomes (a(x+y)+b(x+y)), then ((x+y)) is taken common. In exams look for a common binomial.

Related tags

FactorisationGroupingCommon Binomial

Frequently asked questions

What is the correct answer to this question?

((a+b)(x+y))

Why is this the correct answer?

First it becomes (a(x+y)+b(x+y)), then ((x+y)) is taken common. In exams look for a common binomial.

Which subject and chapter does this question cover?

This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Factorisation.

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  1. 1What is the greatest common factor while factorising (6x+9)?
  2. 2Which is the correct factorisation of (4a+8)?
  3. 3Which common factor will be taken out from (xy+xz)?
  4. 4Choose the correct factorisation of (5m-15).
  5. 5In which of the following expressions is \(3m\) a common factor of every term?
  6. 6Which of the following expressions is a difference of two squares and can be factorised using the identity?
  7. 7Which identity is used to factorise (x^2-9)?
  8. 8Which is the correct factorisation of (x^2-16)?
  9. 9What is the factorisation of (a^2+2ab+b^2)?
  10. 10Which of the following expressions can be factorised using the identity for the difference of two squares, \((a+b)(a-b)\)?
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