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Rima claims that \(2+\sqrt{3}\) is a rational number. Which is the most appropriate argument to prove her claim wrong?

Answer and explanation

Correct answer: If \(2+\sqrt{3}\) were rational, subtracting the rational number \(2\) would make \(\sqrt{3}\) rational, which is a contradiction.

The number \(2\) is rational. If \(2+\sqrt{3}\) were rational, then \((2+\sqrt{3})-2=\sqrt{3}\) would be rational, contradicting the irrationality of \(\sqrt{3}\). Hence the original number is irrational. Exam tip: rational minus rational is rational.

Related tags

Number SystemsIrrational NumbersSquare Root 3Proof By ContradictionRational NumbersProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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