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In which of the following expressions is \(3p\) a common factor of every term?
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Answer and explanation
Correct answer: \(3p^2+12p\)
In option A, both \(3p^2\) and \(12p\) are divisible by \(3p\): \(3p^2+12p=3p(p+4)\). In option B, 12 has no factor \(p\), so \(3p\) cannot be a common factor of all the terms. Exam tip: test a common factor by checking it separately in every term.
Frequently asked questions
What is the correct answer to this question?
\(3p^2+12p\)
Why is this the correct answer?
In option A, both \(3p^2\) and \(12p\) are divisible by \(3p\): \(3p^2+12p=3p(p+4)\). In option B, 12 has no factor \(p\), so \(3p\) cannot be a common factor of all the terms. Exam tip: test a common factor by checking it separately in every term.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Factorisation.
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