वर्गमूल सर्पिल में \( \sqrt{18} \) बनाने के ठीक पहले कौन-सा कर्ण बन चुका होता है?

In the square root spiral, which hypotenuse is already formed just before constructing \( \sqrt{18} \)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \( \sqrt{17} \)

Step 1

Concept

\( \sqrt{18} \) is formed by adding a perpendicular (1) to the previous hypotenuse \( \sqrt{17} \). Always check the previous square root in the sequence.

Step 2

Why this answer is correct

The correct answer is A. \( \sqrt{17} \). \( \sqrt{18} \) is formed by adding a perpendicular (1) to the previous hypotenuse \( \sqrt{17} \). Always check the previous square root in the sequence.

Step 3

Exam Tip

\( \sqrt{18} \) पिछले कर्ण \( \sqrt{17} \) पर (1) लंबवत जोड़कर बनता है। क्रम में हमेशा पिछले वर्गमूल को देखें।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में \( \sqrt{18} \) बनाने के ठीक पहले कौन-सा कर्ण बन चुका होता है? / In the square root spiral, which hypotenuse is already formed just before constructing \( \sqrt{18} \)?

Correct Answer: A. \( \sqrt{17} \). Explanation: \( \sqrt{18} \) पिछले कर्ण \( \sqrt{17} \) पर (1) लंबवत जोड़कर बनता है। क्रम में हमेशा पिछले वर्गमूल को देखें। / \( \sqrt{18} \) is formed by adding a perpendicular (1) to the previous hypotenuse \( \sqrt{17} \). Always check the previous square root in the sequence.

Which concept should I revise for this Mathematics MCQ?

\( \sqrt{18} \) is formed by adding a perpendicular (1) to the previous hypotenuse \( \sqrt{17} \). Always check the previous square root in the sequence.

What exam hint can help solve this Mathematics question?

\( \sqrt{18} \) पिछले कर्ण \( \sqrt{17} \) पर (1) लंबवत जोड़कर बनता है। क्रम में हमेशा पिछले वर्गमूल को देखें।