\(\sqrt{2}\) के प्रमाण में \(a^2\) सम होने से (a) सम क्यों माना जाता है?
In the proof of \(\sqrt{2}\), why is (a) considered even when \(a^2\) is even?
Explanation opens after your attempt
Correct Answer
A. क्योंकि विषम संख्या का वर्ग विषम होता हैBecause the square of an odd number is odd
Concept
If (a) were odd then \(a^2\) would also be odd. Therefore if \(a^2\) is even, (a) is even.
Why this answer is correct
The correct answer is A. क्योंकि विषम संख्या का वर्ग विषम होता है / Because the square of an odd number is odd. If (a) were odd then \(a^2\) would also be odd. Therefore if \(a^2\) is even, (a) is even.
Exam Tip
यदि (a) विषम होता तो \(a^2\) भी विषम होता। इसलिए \(a^2\) सम होने पर (a) सम होगा।
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