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In the proof of √2, what is finally proved false?

Answer and explanation

Correct answer: √2 is rational

The proof uses contradiction. It begins by assuming that √2 is rational and can be written as a/b in lowest terms. The equation a² = 2b² then forces a to be even. Substituting a = 2r gives b² = 2r², so b is also even. This means that a and b share the factor 2, contradicting the claim that a/b was in lowest terms. Consequently, the assumption that √2 is rational is false, and the correct conclusion is that √2 is irrational. Positivity and reality are not disproved: √2 is a positive real number. Thus only option A identifies the statement rejected by the proof.

Related tags

Number-SystemsSquare-Root-2Proof-By-ContradictionProof Of Irrationality Of Square Root 2 And Square Root 3Number SystemsMathematicsClass 9 Mcq

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