\(\sqrt{2}\) के प्रमाण में \(n^2=2k^2\) मिलने के बाद कौन-सा निष्कर्ष अंतिम विरोधाभास की ओर ले जाता है?

In the proof of \(\sqrt{2}\), after getting \(n^2=2k^2\), which conclusion leads to the final contradiction?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (n) सम है(n) is even

Step 1

Concept

\(n^2\) is even, so (n) is also even. Now both (m) and (n) are even.

Step 2

Why this answer is correct

The correct answer is C. (n) सम है / (n) is even. \(n^2\) is even, so (n) is also even. Now both (m) and (n) are even.

Step 3

Exam Tip

\(n^2\) सम है इसलिए (n) भी सम होगा। अब (m) और (n) दोनों सम मिलते हैं।

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Mathematics Answer, Explanation and Revision Hints

\(\sqrt{2}\) के प्रमाण में \(n^2=2k^2\) मिलने के बाद कौन-सा निष्कर्ष अंतिम विरोधाभास की ओर ले जाता है? / In the proof of \(\sqrt{2}\), after getting \(n^2=2k^2\), which conclusion leads to the final contradiction?

Correct Answer: C. (n) सम है / (n) is even. Explanation: \(n^2\) सम है इसलिए (n) भी सम होगा। अब (m) और (n) दोनों सम मिलते हैं। / \(n^2\) is even, so (n) is also even. Now both (m) and (n) are even.

Which concept should I revise for this Mathematics MCQ?

\(n^2\) is even, so (n) is also even. Now both (m) and (n) are even.

What exam hint can help solve this Mathematics question?

\(n^2\) सम है इसलिए (n) भी सम होगा। अब (m) और (n) दोनों सम मिलते हैं।