वर्गमूल सर्पिल में यदि नया कर्ण \(\sqrt{4096}\) है, तो उससे ठीक पहले कौन-सा कर्ण था?

In a square root spiral, if the new hypotenuse is \(\sqrt{4096}\), which hypotenuse was immediately before it?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(\sqrt{4095}\)

Step 1

Concept

If the new hypotenuse is \(\sqrt{n+1}\), the previous hypotenuse is \(\sqrt{n}\). Therefore before \(\sqrt{4096}\), it was \(\sqrt{4095}\).

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{4095}\). If the new hypotenuse is \(\sqrt{n+1}\), the previous hypotenuse is \(\sqrt{n}\). Therefore before \(\sqrt{4096}\), it was \(\sqrt{4095}\).

Step 3

Exam Tip

नया कर्ण \(\sqrt{n+1}\) हो तो पिछला कर्ण \(\sqrt{n}\) होता है। इसलिए \(\sqrt{4096}\) से पहले \(\sqrt{4095}\) था।

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Mathematics Answer, Explanation and Revision Hints

वर्गमूल सर्पिल में यदि नया कर्ण \(\sqrt{4096}\) है, तो उससे ठीक पहले कौन-सा कर्ण था? / In a square root spiral, if the new hypotenuse is \(\sqrt{4096}\), which hypotenuse was immediately before it?

Correct Answer: B. \(\sqrt{4095}\). Explanation: नया कर्ण \(\sqrt{n+1}\) हो तो पिछला कर्ण \(\sqrt{n}\) होता है। इसलिए \(\sqrt{4096}\) से पहले \(\sqrt{4095}\) था। / If the new hypotenuse is \(\sqrt{n+1}\), the previous hypotenuse is \(\sqrt{n}\). Therefore before \(\sqrt{4096}\), it was \(\sqrt{4095}\).

Which concept should I revise for this Mathematics MCQ?

If the new hypotenuse is \(\sqrt{n+1}\), the previous hypotenuse is \(\sqrt{n}\). Therefore before \(\sqrt{4096}\), it was \(\sqrt{4095}\).

What exam hint can help solve this Mathematics question?

नया कर्ण \(\sqrt{n+1}\) हो तो पिछला कर्ण \(\sqrt{n}\) होता है। इसलिए \(\sqrt{4096}\) से पहले \(\sqrt{4095}\) था।