यदि \(y=\sqrt{20}+\sqrt{45}+\sqrt{80}\) है तो \(y^2\) का मान क्या है?
If \(y=\sqrt{20}+\sqrt{45}+\sqrt{80}\), what is the value of \(y^2\)?
Explanation opens after your attempt
Correct Answer
A. (405)
Concept
\(\sqrt{20}=2\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), and \(\sqrt{80}=4\sqrt{5}\). So \(y=9\sqrt{5}\) and \(y^2=405\).
Why this answer is correct
The correct answer is A. (405). \(\sqrt{20}=2\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\), and \(\sqrt{80}=4\sqrt{5}\). So \(y=9\sqrt{5}\) and \(y^2=405\).
Exam Tip
\(\sqrt{20}=2\sqrt{5}\), \(\sqrt{45}=3\sqrt{5}\) और \(\sqrt{80}=4\sqrt{5}\) है। इसलिए \(y=9\sqrt{5}\) और \(y^2=405\) है।
Login to save your score, XP, coins and progress.