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If \(x=\sqrt{n}\), which condition on \(n\) guarantees that \(x\) is irrational?

Answer and explanation

Correct answer: \(n\) is a natural number that is not a perfect square

When \(n\) is a natural number that is not a perfect square, \(\sqrt{n}\) cannot be expressed as a ratio of two integers, so it is irrational. Merely being an integer is not enough: for example, if \(n=4\), then \(\sqrt{4}=2\), which is rational. Exam tip: The square root of a natural number is rational only when the number is a perfect square.

Related tags

Real NumbersIrrational NumbersSquare RootsPerfect SquaresNumber SystemsMathematicsClass 9 Mcq

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