यदि \(x=\sqrt{3}+\sqrt{2}\) और \(y=\sqrt{3}-\sqrt{2}\) हैं, तो \(\frac{x}{y}\) का मान क्या है?
If \(x=\sqrt{3}+\sqrt{2}\) and \(y=\sqrt{3}-\sqrt{2}\), what is the value of \(\frac{x}{y}\)?
Explanation opens after your attempt
Correct Answer
A. \(5+2\sqrt{6}\)
Concept
The conjugate of the denominator is \(\sqrt{3}+\sqrt{2}\) and the denominator becomes (1). So the value is (\(\sqrt{3}+\sqrt{2}\)2=5+2\sqrt{6}).
Why this answer is correct
The correct answer is A. \(5+2\sqrt{6}\). The conjugate of the denominator is \(\sqrt{3}+\sqrt{2}\) and the denominator becomes (1). So the value is (\(\sqrt{3}+\sqrt{2}\)2=5+2\sqrt{6}).
Exam Tip
हर का संयुग्मी \(\sqrt{3}+\sqrt{2}\) है और हर (1) बनता है। इसलिए मान (\(\sqrt{3}+\sqrt{2}\)2=5+2\sqrt{6}) है।
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