\(x^2+ax+20\) में यदि गुणनखंड ((x+4)(x+5)) हैं तो (a) क्या है?

If the factors of \(x^2+ax+20\) are ((x+4)(x+5)), what is (a)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (9)

Step 1

Concept

((x+4)(x+5)=x-2+9x+20). Therefore (a=9).

Step 2

Why this answer is correct

The correct answer is A. (9). ((x+4)(x+5)=x-2+9x+20). Therefore (a=9).

Step 3

Exam Tip

((x+4)(x+5)=x-2+9x+20) होता है। इसलिए (a=9) है।

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Mathematics Answer, Explanation and Revision Hints

\(x^2+ax+20\) में यदि गुणनखंड ((x+4)(x+5)) हैं तो (a) क्या है? / If the factors of \(x^2+ax+20\) are ((x+4)(x+5)), what is (a)?

Correct Answer: A. (9). Explanation: ((x+4)(x+5)=x-2+9x+20) होता है। इसलिए (a=9) है। / ((x+4)(x+5)=x-2+9x+20). Therefore (a=9).

Which concept should I revise for this Mathematics MCQ?

((x+4)(x+5)=x-2+9x+20). Therefore (a=9).

What exam hint can help solve this Mathematics question?

((x+4)(x+5)=x-2+9x+20) होता है। इसलिए (a=9) है।