\(x^2+ax+20\) में यदि गुणनखंड ((x+4)(x+5)) हैं तो (a) क्या है?
If the factors of \(x^2+ax+20\) are ((x+4)(x+5)), what is (a)?
Explanation opens after your attempt
A. (9)
Concept
((x+4)(x+5)=x-2+9x+20). Therefore (a=9).
Why this answer is correct
The correct answer is A. (9). ((x+4)(x+5)=x-2+9x+20). Therefore (a=9).
Exam Tip
((x+4)(x+5)=x-2+9x+20) होता है। इसलिए (a=9) है।
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