यदि (T(x)=x-3\(x^5-2x^3+1\)-x-8+2x-6+5x), तो (T(x)) की डिग्री क्या है?

If (T(x)=x-3\(x^5-2x^3+1\)-x-8+2x-6+5x), what is the degree of (T(x))?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

C. (3)

Step 1

Concept

On expanding, we get \(x^8-2x^6+x^3-x^8+2x^6+5x\). Higher terms cancel and the degree remains (3).

Step 2

Why this answer is correct

The correct answer is C. (3). On expanding, we get \(x^8-2x^6+x^3-x^8+2x^6+5x\). Higher terms cancel and the degree remains (3).

Step 3

Exam Tip

फैलाने पर \(x^8-2x^6+x^3-x^8+2x^6+5x\) मिलता है। बड़े पद कट जाते हैं और डिग्री (3) रहती है।

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Mathematics Answer, Explanation and Revision Hints

यदि (T(x)=x-3\(x^5-2x^3+1\)-x-8+2x-6+5x), तो (T(x)) की डिग्री क्या है? / If (T(x)=x-3\(x^5-2x^3+1\)-x-8+2x-6+5x), what is the degree of (T(x))?

Correct Answer: C. (3). Explanation: फैलाने पर \(x^8-2x^6+x^3-x^8+2x^6+5x\) मिलता है। बड़े पद कट जाते हैं और डिग्री (3) रहती है। / On expanding, we get \(x^8-2x^6+x^3-x^8+2x^6+5x\). Higher terms cancel and the degree remains (3).

Which concept should I revise for this Mathematics MCQ?

On expanding, we get \(x^8-2x^6+x^3-x^8+2x^6+5x\). Higher terms cancel and the degree remains (3).

What exam hint can help solve this Mathematics question?

फैलाने पर \(x^8-2x^6+x^3-x^8+2x^6+5x\) मिलता है। बड़े पद कट जाते हैं और डिग्री (3) रहती है।