यदि \(t=\sqrt{31}+5\) है तो \(t+\frac{6}{t}\) का मान क्या है?
If \(t=\sqrt{31}+5\), what is the value of \(t+\frac{6}{t}\)?
Explanation opens after your attempt
Correct Answer
A. \(2\sqrt{31}\)
Concept
\(\frac{6}{\sqrt{31}+5}=\sqrt{31}-5\) because the denominator becomes (31-25=6). So the sum is \(2\sqrt{31}\).
Why this answer is correct
The correct answer is A. \(2\sqrt{31}\). \(\frac{6}{\sqrt{31}+5}=\sqrt{31}-5\) because the denominator becomes (31-25=6). So the sum is \(2\sqrt{31}\).
Exam Tip
\(\frac{6}{\sqrt{31}+5}=\sqrt{31}-5\) है क्योंकि हर (31-25=6) बनता है। इसलिए योग \(2\sqrt{31}\) है।
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