यदि \(t=\sqrt{13}+3\) है तो \(t+\frac{4}{t}\) का मान क्या है?

If \(t=\sqrt{13}+3\), what is the value of \(t+\frac{4}{t}\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(2\sqrt{13}\)

Step 1

Concept

\(\frac{4}{\sqrt{13}+3}=\sqrt{13}-3\) because the denominator becomes (13-9=4). Therefore the sum is \(2\sqrt{13}\).

Step 2

Why this answer is correct

The correct answer is A. \(2\sqrt{13}\). \(\frac{4}{\sqrt{13}+3}=\sqrt{13}-3\) because the denominator becomes (13-9=4). Therefore the sum is \(2\sqrt{13}\).

Step 3

Exam Tip

\(\frac{4}{\sqrt{13}+3}=\sqrt{13}-3\) है क्योंकि हर (13-9=4) बनता है। इसलिए योग \(2\sqrt{13}\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(t=\sqrt{13}+3\) है तो \(t+\frac{4}{t}\) का मान क्या है? / If \(t=\sqrt{13}+3\), what is the value of \(t+\frac{4}{t}\)?

Correct Answer: A. \(2\sqrt{13}\). Explanation: \(\frac{4}{\sqrt{13}+3}=\sqrt{13}-3\) है क्योंकि हर (13-9=4) बनता है। इसलिए योग \(2\sqrt{13}\) है। / \(\frac{4}{\sqrt{13}+3}=\sqrt{13}-3\) because the denominator becomes (13-9=4). Therefore the sum is \(2\sqrt{13}\).

Which concept should I revise for this Mathematics MCQ?

\(\frac{4}{\sqrt{13}+3}=\sqrt{13}-3\) because the denominator becomes (13-9=4). Therefore the sum is \(2\sqrt{13}\).

What exam hint can help solve this Mathematics question?

\(\frac{4}{\sqrt{13}+3}=\sqrt{13}-3\) है क्योंकि हर (13-9=4) बनता है। इसलिए योग \(2\sqrt{13}\) है।