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If \(\sqrt{3}\) is assumed to be rational and written as \(\frac{p}{q}\), which condition is necessary for \(p\) and \(q\)?

Answer and explanation

Correct answer: \(p\) and \(q\) are coprime

In proof by contradiction, \(\sqrt{3}=\frac{p}{q}\) is taken in lowest terms, so \(p\) and \(q\) must be coprime. Then \(p^2=3q^2\) implies both are divisible by 3, giving a contradiction. Exam tip: lowest terms means coprime.

Related tags

Number SystemsIrrational NumbersSquare Root 3Proof By ContradictionCoprime IntegersProof Of Irrationality Of Square Root 2 And Square Root 3MathematicsClass 9 Mcq

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