यदि \(s=\sqrt{75}+\sqrt{192}\) है तो \(\frac{s}{\sqrt{3}}\) का मान क्या है?
If \(s=\sqrt{75}+\sqrt{192}\), what is the value of \(\frac{s}{\sqrt{3}}\)?
Explanation opens after your attempt
A. (13)
Concept
\(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{192}=8\sqrt{3}\), so \(s=13\sqrt{3}\). Dividing by \(\sqrt{3}\) gives (13).
Why this answer is correct
The correct answer is A. (13). \(\sqrt{75}=5\sqrt{3}\) and \(\sqrt{192}=8\sqrt{3}\), so \(s=13\sqrt{3}\). Dividing by \(\sqrt{3}\) gives (13).
Exam Tip
\(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{192}=8\sqrt{3}\), इसलिए \(s=13\sqrt{3}\) है। \(\sqrt{3}\) से भाग देने पर (13) मिलता है।
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