यदि \(s=\sqrt{27}+\sqrt{12}\) है, तो \(\frac{s}{\sqrt{3}}\) का मान क्या है?
If \(s=\sqrt{27}+\sqrt{12}\), what is the value of \(\frac{s}{\sqrt{3}}\)?
Explanation opens after your attempt
Correct Answer
A. (5)
Concept
\(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\), so \(s=5\sqrt{3}\). Dividing by \(\sqrt{3}\) gives (5).
Why this answer is correct
The correct answer is A. (5). \(\sqrt{27}=3\sqrt{3}\) and \(\sqrt{12}=2\sqrt{3}\), so \(s=5\sqrt{3}\). Dividing by \(\sqrt{3}\) gives (5).
Exam Tip
\(\sqrt{27}=3\sqrt{3}\) और \(\sqrt{12}=2\sqrt{3}\), इसलिए \(s=5\sqrt{3}\) है। \(\sqrt{3}\) से भाग देने पर (5) मिलता है।
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