यदि \(r=\sqrt{17}+\sqrt{11}\) और \(s=\sqrt{17}-\sqrt{11}\) हैं तो \(r^2-s^2\) का मान क्या है?

If \(r=\sqrt{17}+\sqrt{11}\) and \(s=\sqrt{17}-\sqrt{11}\), what is the value of \(r^2-s^2\)?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. \(4\sqrt{187}\)

Step 1

Concept

(r-2-s-2=(r-s)(r+s)), where \(r-s=2\sqrt{11}\) and \(r+s=2\sqrt{17}\). So the value is \(4\sqrt{187}\).

Step 2

Why this answer is correct

The correct answer is A. \(4\sqrt{187}\). (r-2-s-2=(r-s)(r+s)), where \(r-s=2\sqrt{11}\) and \(r+s=2\sqrt{17}\). So the value is \(4\sqrt{187}\).

Step 3

Exam Tip

(r-2-s-2=(r-s)(r+s)) है जहाँ \(r-s=2\sqrt{11}\) और \(r+s=2\sqrt{17}\) है। इसलिए मान \(4\sqrt{187}\) है।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(r=\sqrt{17}+\sqrt{11}\) और \(s=\sqrt{17}-\sqrt{11}\) हैं तो \(r^2-s^2\) का मान क्या है? / If \(r=\sqrt{17}+\sqrt{11}\) and \(s=\sqrt{17}-\sqrt{11}\), what is the value of \(r^2-s^2\)?

Correct Answer: A. \(4\sqrt{187}\). Explanation: (r-2-s-2=(r-s)(r+s)) है जहाँ \(r-s=2\sqrt{11}\) और \(r+s=2\sqrt{17}\) है। इसलिए मान \(4\sqrt{187}\) है। / (r-2-s-2=(r-s)(r+s)), where \(r-s=2\sqrt{11}\) and \(r+s=2\sqrt{17}\). So the value is \(4\sqrt{187}\).

Which concept should I revise for this Mathematics MCQ?

(r-2-s-2=(r-s)(r+s)), where \(r-s=2\sqrt{11}\) and \(r+s=2\sqrt{17}\). So the value is \(4\sqrt{187}\).

What exam hint can help solve this Mathematics question?

(r-2-s-2=(r-s)(r+s)) है जहाँ \(r-s=2\sqrt{11}\) और \(r+s=2\sqrt{17}\) है। इसलिए मान \(4\sqrt{187}\) है।