यदि सर्पिल में \( \sqrt{120} \) तक बिंदु बने हैं, तो \( \sqrt{121} \) बनाने के बाद दूरी क्या होगी?
If points are constructed up to \( \sqrt{120} \) in the spiral, what will the distance be after constructing \( \sqrt{121} \)?
Explanation opens after your attempt
B. (11)
Concept
\( \sqrt{121}=11 \), so the distance will be (11) units. A perfect square gives an integer square root.
Why this answer is correct
The correct answer is B. (11). \( \sqrt{121}=11 \), so the distance will be (11) units. A perfect square gives an integer square root.
Exam Tip
\( \sqrt{121}=11 \), इसलिए दूरी (11) इकाई होगी। पूर्ण वर्ग आने पर वर्गमूल पूर्णांक बन जाता है।
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