यदि \(OP=\sqrt{15}\), (PQ=1), और (PQ) लंब नहीं बल्कि तिरछा है, तो क्या \(OQ=\sqrt{16}\) निश्चित होगा?
If \(OP=\sqrt{15}\), (PQ=1), and (PQ) is slanting instead of perpendicular, is \(OQ=\sqrt{16}\) certain?
Explanation opens after your attempt
B. नहीं, क्योंकि पाइथागोरस प्रमेय के लिए समकोण जरूरी हैNo, because a right angle is necessary for Pythagoras theorem
Concept
\(\sqrt{16}\) is certain only when the new segment is perpendicular to the previous hypotenuse. Without a right angle, Pythagoras theorem cannot be applied.
Why this answer is correct
The correct answer is B. नहीं, क्योंकि पाइथागोरस प्रमेय के लिए समकोण जरूरी है / No, because a right angle is necessary for Pythagoras theorem. \(\sqrt{16}\) is certain only when the new segment is perpendicular to the previous hypotenuse. Without a right angle, Pythagoras theorem cannot be applied.
Exam Tip
\(\sqrt{16}\) तभी निश्चित होगा जब नया खंड पिछले कर्ण पर लंब हो। समकोण के बिना पाइथागोरस प्रमेय नहीं लगेगा।
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