यदि \(OP=\sqrt{15}\), (PQ=1), और (PQ) लंब नहीं बल्कि तिरछा है, तो क्या \(OQ=\sqrt{16}\) निश्चित होगा?

If \(OP=\sqrt{15}\), (PQ=1), and (PQ) is slanting instead of perpendicular, is \(OQ=\sqrt{16}\) certain?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. नहीं, क्योंकि पाइथागोरस प्रमेय के लिए समकोण जरूरी हैNo, because a right angle is necessary for Pythagoras theorem

Step 1

Concept

\(\sqrt{16}\) is certain only when the new segment is perpendicular to the previous hypotenuse. Without a right angle, Pythagoras theorem cannot be applied.

Step 2

Why this answer is correct

The correct answer is B. नहीं, क्योंकि पाइथागोरस प्रमेय के लिए समकोण जरूरी है / No, because a right angle is necessary for Pythagoras theorem. \(\sqrt{16}\) is certain only when the new segment is perpendicular to the previous hypotenuse. Without a right angle, Pythagoras theorem cannot be applied.

Step 3

Exam Tip

\(\sqrt{16}\) तभी निश्चित होगा जब नया खंड पिछले कर्ण पर लंब हो। समकोण के बिना पाइथागोरस प्रमेय नहीं लगेगा।

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यदि \(OP=\sqrt{15}\), (PQ=1), और (PQ) लंब नहीं बल्कि तिरछा है, तो क्या \(OQ=\sqrt{16}\) निश्चित होगा? / If \(OP=\sqrt{15}\), (PQ=1), and (PQ) is slanting instead of perpendicular, is \(OQ=\sqrt{16}\) certain?

Correct Answer: B. नहीं, क्योंकि पाइथागोरस प्रमेय के लिए समकोण जरूरी है / No, because a right angle is necessary for Pythagoras theorem. Explanation: \(\sqrt{16}\) तभी निश्चित होगा जब नया खंड पिछले कर्ण पर लंब हो। समकोण के बिना पाइथागोरस प्रमेय नहीं लगेगा। / \(\sqrt{16}\) is certain only when the new segment is perpendicular to the previous hypotenuse. Without a right angle, Pythagoras theorem cannot be applied.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{16}\) is certain only when the new segment is perpendicular to the previous hypotenuse. Without a right angle, Pythagoras theorem cannot be applied.

What exam hint can help solve this Mathematics question?

\(\sqrt{16}\) तभी निश्चित होगा जब नया खंड पिछले कर्ण पर लंब हो। समकोण के बिना पाइथागोरस प्रमेय नहीं लगेगा।