यदि \(OP_a=\sqrt{a}\) और \(OP_b=\sqrt{b}\), जहाँ (b=a+5), तो \(OP_b^2-OP_a^2\) कितना होगा?

If \(OP_a=\sqrt{a}\) and \(OP_b=\sqrt{b}\), where (b=a+5), what is \(OP_b^2-OP_a^2\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

C. (5)

Step 1

Concept

\(OP_b^2=b\) and \(OP_a^2=a\), so the difference is (b-a=5). Square the lengths to remove square roots.

Step 2

Why this answer is correct

The correct answer is C. (5). \(OP_b^2=b\) and \(OP_a^2=a\), so the difference is (b-a=5). Square the lengths to remove square roots.

Step 3

Exam Tip

\(OP_b^2=b\) और \(OP_a^2=a\), इसलिए अंतर (b-a=5) है। वर्गमूल हटाने के लिए वर्ग लें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(OP_a=\sqrt{a}\) और \(OP_b=\sqrt{b}\), जहाँ (b=a+5), तो \(OP_b^2-OP_a^2\) कितना होगा? / If \(OP_a=\sqrt{a}\) and \(OP_b=\sqrt{b}\), where (b=a+5), what is \(OP_b^2-OP_a^2\)?

Correct Answer: C. (5). Explanation: \(OP_b^2=b\) और \(OP_a^2=a\), इसलिए अंतर (b-a=5) है। वर्गमूल हटाने के लिए वर्ग लें। / \(OP_b^2=b\) and \(OP_a^2=a\), so the difference is (b-a=5). Square the lengths to remove square roots.

Which concept should I revise for this Mathematics MCQ?

\(OP_b^2=b\) and \(OP_a^2=a\), so the difference is (b-a=5). Square the lengths to remove square roots.

What exam hint can help solve this Mathematics question?

\(OP_b^2=b\) और \(OP_a^2=a\), इसलिए अंतर (b-a=5) है। वर्गमूल हटाने के लिए वर्ग लें।