यदि सर्पिल में \(\sqrt{2}\) से गिनती शुरू करें, तो (25)वां कर्ण कौन सा होगा?
If counting starts from \(\sqrt{2}\) in the spiral, what will be the (25)th hypotenuse?
Explanation opens after your attempt
B. \(\sqrt{26}\)
Concept
\(\sqrt{2}\) is the first hypotenuse, so the (25)th hypotenuse is \(\sqrt{25+1}=\sqrt{26}\). Keep the starting point of counting clear.
Why this answer is correct
The correct answer is B. \(\sqrt{26}\). \(\sqrt{2}\) is the first hypotenuse, so the (25)th hypotenuse is \(\sqrt{25+1}=\sqrt{26}\). Keep the starting point of counting clear.
Exam Tip
\(\sqrt{2}\) पहला कर्ण है, इसलिए (25)वां कर्ण \(\sqrt{25+1}=\sqrt{26}\) होगा। गिनती का आरंभ स्पष्ट रखें।
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