यदि सर्पिल में \(\sqrt{2}\) से गिनती शुरू करें, तो (25)वां कर्ण कौन सा होगा?

If counting starts from \(\sqrt{2}\) in the spiral, what will be the (25)th hypotenuse?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

B. \(\sqrt{26}\)

Step 1

Concept

\(\sqrt{2}\) is the first hypotenuse, so the (25)th hypotenuse is \(\sqrt{25+1}=\sqrt{26}\). Keep the starting point of counting clear.

Step 2

Why this answer is correct

The correct answer is B. \(\sqrt{26}\). \(\sqrt{2}\) is the first hypotenuse, so the (25)th hypotenuse is \(\sqrt{25+1}=\sqrt{26}\). Keep the starting point of counting clear.

Step 3

Exam Tip

\(\sqrt{2}\) पहला कर्ण है, इसलिए (25)वां कर्ण \(\sqrt{25+1}=\sqrt{26}\) होगा। गिनती का आरंभ स्पष्ट रखें।

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Mathematics Answer, Explanation and Revision Hints

यदि सर्पिल में \(\sqrt{2}\) से गिनती शुरू करें, तो (25)वां कर्ण कौन सा होगा? / If counting starts from \(\sqrt{2}\) in the spiral, what will be the (25)th hypotenuse?

Correct Answer: B. \(\sqrt{26}\). Explanation: \(\sqrt{2}\) पहला कर्ण है, इसलिए (25)वां कर्ण \(\sqrt{25+1}=\sqrt{26}\) होगा। गिनती का आरंभ स्पष्ट रखें। / \(\sqrt{2}\) is the first hypotenuse, so the (25)th hypotenuse is \(\sqrt{25+1}=\sqrt{26}\). Keep the starting point of counting clear.

Which concept should I revise for this Mathematics MCQ?

\(\sqrt{2}\) is the first hypotenuse, so the (25)th hypotenuse is \(\sqrt{25+1}=\sqrt{26}\). Keep the starting point of counting clear.

What exam hint can help solve this Mathematics question?

\(\sqrt{2}\) पहला कर्ण है, इसलिए (25)वां कर्ण \(\sqrt{25+1}=\sqrt{26}\) होगा। गिनती का आरंभ स्पष्ट रखें।