यदि (7) नए चरण बनाने के बाद कर्ण \(\sqrt{29}\) मिला, तो शुरुआत में कौन सा कर्ण था?

If after (7) new steps the hypotenuse becomes \(\sqrt{29}\), what was the starting hypotenuse?

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Correct Answer

C. \(\sqrt{22}\)

Step 1

Concept

Going (7) steps backward gives (29-7=22). Therefore, the starting hypotenuse was \(\sqrt{22}\).

Step 2

Why this answer is correct

The correct answer is C. \(\sqrt{22}\). Going (7) steps backward gives (29-7=22). Therefore, the starting hypotenuse was \(\sqrt{22}\).

Step 3

Exam Tip

(7) चरण पीछे जाने पर (29-7=22) मिलता है। इसलिए शुरुआत का कर्ण \(\sqrt{22}\) था।

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यदि (7) नए चरण बनाने के बाद कर्ण \(\sqrt{29}\) मिला, तो शुरुआत में कौन सा कर्ण था? / If after (7) new steps the hypotenuse becomes \(\sqrt{29}\), what was the starting hypotenuse?

Correct Answer: C. \(\sqrt{22}\). Explanation: (7) चरण पीछे जाने पर (29-7=22) मिलता है। इसलिए शुरुआत का कर्ण \(\sqrt{22}\) था। / Going (7) steps backward gives (29-7=22). Therefore, the starting hypotenuse was \(\sqrt{22}\).

Which concept should I revise for this Mathematics MCQ?

Going (7) steps backward gives (29-7=22). Therefore, the starting hypotenuse was \(\sqrt{22}\).

What exam hint can help solve this Mathematics question?

(7) चरण पीछे जाने पर (29-7=22) मिलता है। इसलिए शुरुआत का कर्ण \(\sqrt{22}\) था।