यदि कोई विद्यार्थी \(\sqrt{18}+1=\sqrt{19}\) लिखकर अगला कर्ण बताता है, तो सही सुधार कौन-सा है?

If a student writes \(\sqrt{18}+1=\sqrt{19}\) to find the next hypotenuse, what is the correct correction?

Author: Muft Shiksha Editorial Team Published:
Explanation opens after your attempt
Correct Answer

A. (\sqrt{\(\sqrt{18}\)2+12}=\sqrt{19})

Step 1

Concept

In a square root spiral, the hypotenuse is formed by the sum of squares. Do not treat \(\sqrt{18}+1\) as \(\sqrt{19}\).

Step 2

Why this answer is correct

The correct answer is A. (\sqrt{\(\sqrt{18}\)2+12}=\sqrt{19}). In a square root spiral, the hypotenuse is formed by the sum of squares. Do not treat \(\sqrt{18}+1\) as \(\sqrt{19}\).

Step 3

Exam Tip

वर्गमूल सर्पिल में कर्ण वर्गों के योग से बनता है। \(\sqrt{18}+1\) को \(\sqrt{19}\) नहीं मानना चाहिए।

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यदि कोई विद्यार्थी \(\sqrt{18}+1=\sqrt{19}\) लिखकर अगला कर्ण बताता है, तो सही सुधार कौन-सा है? / If a student writes \(\sqrt{18}+1=\sqrt{19}\) to find the next hypotenuse, what is the correct correction?

Correct Answer: A. (\sqrt{\(\sqrt{18}\)2+12}=\sqrt{19}). Explanation: वर्गमूल सर्पिल में कर्ण वर्गों के योग से बनता है। \(\sqrt{18}+1\) को \(\sqrt{19}\) नहीं मानना चाहिए। / In a square root spiral, the hypotenuse is formed by the sum of squares. Do not treat \(\sqrt{18}+1\) as \(\sqrt{19}\).

Which concept should I revise for this Mathematics MCQ?

In a square root spiral, the hypotenuse is formed by the sum of squares. Do not treat \(\sqrt{18}+1\) as \(\sqrt{19}\).

What exam hint can help solve this Mathematics question?

वर्गमूल सर्पिल में कर्ण वर्गों के योग से बनता है। \(\sqrt{18}+1\) को \(\sqrt{19}\) नहीं मानना चाहिए।