यदि \(a=\sqrt{5}+\sqrt{2}\) है तो \(a^2+\frac{1}{a^2}\) का मान क्या है?
If \(a=\sqrt{5}+\sqrt{2}\), what is the value of \(a^2+\frac{1}{a^2}\)?
Explanation opens after your attempt
Correct Answer
A. (98)
Concept
\(a^2=7+2\sqrt{10}\) and \( \frac{1}{a^2} \) is not simply \(7-2\sqrt{10}\) because (a\(\sqrt{5}-\sqrt{2}\)=3). Check options carefully using reciprocal rules.
Why this answer is correct
The correct answer is A. (98). \(a^2=7+2\sqrt{10}\) and \( \frac{1}{a^2} \) is not simply \(7-2\sqrt{10}\) because (a\(\sqrt{5}-\sqrt{2}\)=3). Check options carefully using reciprocal rules.
Exam Tip
\(a^2=7+2\sqrt{10}\) और \( \frac{1}{a^2}=7-2\sqrt{10} \) नहीं है क्योंकि (a\(\sqrt{5}-\sqrt{2}\)=3)। सही मान सीधे (a-2+\frac{1}{a-2}=\frac{\(a^2\)2+1}{a-2}) से कठिन है इसलिए विकल्प जाँचें।
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