यदि \(a=\sqrt{12}+\sqrt{75}\) और \(b=\sqrt{48}\) हैं तो (a-b) का सरल रूप क्या है?
If \(a=\sqrt{12}+\sqrt{75}\) and \(b=\sqrt{48}\), what is the simplified form of (a-b)?
Explanation opens after your attempt
C. \(3\sqrt{3}\)
Concept
\(\sqrt{12}=2\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\), and \(\sqrt{48}=4\sqrt{3}\). Therefore \(a-b=3\sqrt{3}\).
Why this answer is correct
The correct answer is C. \(3\sqrt{3}\). \(\sqrt{12}=2\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\), and \(\sqrt{48}=4\sqrt{3}\). Therefore \(a-b=3\sqrt{3}\).
Exam Tip
\(\sqrt{12}=2\sqrt{3}\), \(\sqrt{75}=5\sqrt{3}\) और \(\sqrt{48}=4\sqrt{3}\) है। इसलिए \(a-b=3\sqrt{3}\) है।
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