यदि एक आयत की लंबाई \(\sqrt{11}+\sqrt{6}\) और चौड़ाई \(\sqrt{11}-\sqrt{6}\) है तो क्षेत्रफल क्या होगा?
If a rectangle has length \(\sqrt{11}+\sqrt{6}\) and breadth \(\sqrt{11}-\sqrt{6}\), what will be its area?
Explanation opens after your attempt
Correct Answer
B. (5)
Concept
Area is (\(\sqrt{11}+\sqrt{6}\)\(\sqrt{11}-\sqrt{6}\)=11-6=5). Conjugate dimensions can give a rational area.
Why this answer is correct
The correct answer is B. (5). Area is (\(\sqrt{11}+\sqrt{6}\)\(\sqrt{11}-\sqrt{6}\)=11-6=5). Conjugate dimensions can give a rational area.
Exam Tip
क्षेत्रफल (\(\sqrt{11}+\sqrt{6}\)\(\sqrt{11}-\sqrt{6}\)=11-6=5) है। संयुग्मी आयामों से परिमेय क्षेत्रफल मिल सकता है।
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