यदि एक आयत की लंबाई \(3+\sqrt{2}\) और चौड़ाई \(3-\sqrt{2}\) है, तो क्षेत्रफल क्या होगा?
If a rectangle has length \(3+\sqrt{2}\) and breadth \(3-\sqrt{2}\), what will be its area?
Explanation opens after your attempt
A. (7)
Concept
Area is (\(3+\sqrt{2}\)\(3-\sqrt{2}\)=9-2=7). Multiplying conjugate dimensions can give a rational area.
Why this answer is correct
The correct answer is A. (7). Area is (\(3+\sqrt{2}\)\(3-\sqrt{2}\)=9-2=7). Multiplying conjugate dimensions can give a rational area.
Exam Tip
क्षेत्रफल (\(3+\sqrt{2}\)\(3-\sqrt{2}\)=9-2=7) है। संयुग्मी आयामों का गुणन परिमेय क्षेत्रफल दे सकता है।
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