यदि एक आयत की लंबाई \(3+\sqrt{2}\) और चौड़ाई \(3-\sqrt{2}\) है, तो क्षेत्रफल क्या होगा?

If a rectangle has length \(3+\sqrt{2}\) and breadth \(3-\sqrt{2}\), what will be its area?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

A. (7)

Step 1

Concept

Area is (\(3+\sqrt{2}\)\(3-\sqrt{2}\)=9-2=7). Multiplying conjugate dimensions can give a rational area.

Step 2

Why this answer is correct

The correct answer is A. (7). Area is (\(3+\sqrt{2}\)\(3-\sqrt{2}\)=9-2=7). Multiplying conjugate dimensions can give a rational area.

Step 3

Exam Tip

क्षेत्रफल (\(3+\sqrt{2}\)\(3-\sqrt{2}\)=9-2=7) है। संयुग्मी आयामों का गुणन परिमेय क्षेत्रफल दे सकता है।

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यदि एक आयत की लंबाई \(3+\sqrt{2}\) और चौड़ाई \(3-\sqrt{2}\) है, तो क्षेत्रफल क्या होगा? / If a rectangle has length \(3+\sqrt{2}\) and breadth \(3-\sqrt{2}\), what will be its area?

Correct Answer: A. (7). Explanation: क्षेत्रफल (\(3+\sqrt{2}\)\(3-\sqrt{2}\)=9-2=7) है। संयुग्मी आयामों का गुणन परिमेय क्षेत्रफल दे सकता है। / Area is (\(3+\sqrt{2}\)\(3-\sqrt{2}\)=9-2=7). Multiplying conjugate dimensions can give a rational area.

Which concept should I revise for this Mathematics MCQ?

Area is (\(3+\sqrt{2}\)\(3-\sqrt{2}\)=9-2=7). Multiplying conjugate dimensions can give a rational area.

What exam hint can help solve this Mathematics question?

क्षेत्रफल (\(3+\sqrt{2}\)\(3-\sqrt{2}\)=9-2=7) है। संयुग्मी आयामों का गुणन परिमेय क्षेत्रफल दे सकता है।