यदि \(a_n=96\left(\frac{1}{2}\right)^{n-1}\) है, तो \(a_3+a_6\) का मान क्या है?
If \(a_n=96\left(\frac{1}{2}\right)^{n-1}\), what is the value of \(a_3+a_6\)?
Explanation opens after your attempt
A. (27)
Concept
\(a_3=24\) and \(a_6=3\), so the sum is (27). Use powers carefully with a fractional ratio.
Why this answer is correct
The correct answer is A. (27). \(a_3=24\) and \(a_6=3\), so the sum is (27). Use powers carefully with a fractional ratio.
Exam Tip
\(a_3=24\) और \(a_6=3\), इसलिए योग (27) है। भिन्न अनुपात में घात सावधानी से लगाएं।
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