यदि \(a_1=6\) और \(a_{n+1}=a_n+\frac{a_n}{2}+n\) है तो \(a_3\) क्या होगा?

If \(a_1=6\) and \(a_{n+1}=a_n+\frac{a_n}{2}+n\), what is \(a_3\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (17)

Step 1

Concept

\(a_2=6+3+1=10\) and \(a_3=10+5+2=17\). Exam tip: take half of the previous term and add (n).

Step 2

Why this answer is correct

The correct answer is B. (17). \(a_2=6+3+1=10\) and \(a_3=10+5+2=17\). Exam tip: take half of the previous term and add (n).

Step 3

Exam Tip

\(a_2=6+3+1=10\) और \(a_3=10+5+2=17\) है। पिछले पद का आधा लेकर (n) जोड़ें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=6\) और \(a_{n+1}=a_n+\frac{a_n}{2}+n\) है तो \(a_3\) क्या होगा? / If \(a_1=6\) and \(a_{n+1}=a_n+\frac{a_n}{2}+n\), what is \(a_3\)?

Correct Answer: B. (17). Explanation: \(a_2=6+3+1=10\) और \(a_3=10+5+2=17\) है। पिछले पद का आधा लेकर (n) जोड़ें। / \(a_2=6+3+1=10\) and \(a_3=10+5+2=17\). Exam tip: take half of the previous term and add (n).

Which concept should I revise for this Mathematics MCQ?

\(a_2=6+3+1=10\) and \(a_3=10+5+2=17\). Exam tip: take half of the previous term and add (n).

What exam hint can help solve this Mathematics question?

\(a_2=6+3+1=10\) और \(a_3=10+5+2=17\) है। पिछले पद का आधा लेकर (n) जोड़ें।