यदि \(a_1=3\) और \(a_{n+1}=2a_n+n^2\) है तो \(a_5\) क्या होगा?

If \(a_1=3\) and \(a_{n+1}=2a_n+n^2\), what will \(a_5\) be?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (91)

Step 1

Concept

The terms are (3,7,18,45,91), so \(a_5=91\). Exam tip: \(n^2\) changes at each recursive step.

Step 2

Why this answer is correct

The correct answer is B. (91). The terms are (3,7,18,45,91), so \(a_5=91\). Exam tip: \(n^2\) changes at each recursive step.

Step 3

Exam Tip

पद (3,7,18,45,91) मिलते हैं इसलिए \(a_5=91\) है। पुनरावर्ती नियम में \(n^2\) हर चरण बदलता है।

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Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=3\) और \(a_{n+1}=2a_n+n^2\) है तो \(a_5\) क्या होगा? / If \(a_1=3\) and \(a_{n+1}=2a_n+n^2\), what will \(a_5\) be?

Correct Answer: B. (91). Explanation: पद (3,7,18,45,91) मिलते हैं इसलिए \(a_5=91\) है। पुनरावर्ती नियम में \(n^2\) हर चरण बदलता है। / The terms are (3,7,18,45,91), so \(a_5=91\). Exam tip: \(n^2\) changes at each recursive step.

Which concept should I revise for this Mathematics MCQ?

The terms are (3,7,18,45,91), so \(a_5=91\). Exam tip: \(n^2\) changes at each recursive step.

What exam hint can help solve this Mathematics question?

पद (3,7,18,45,91) मिलते हैं इसलिए \(a_5=91\) है। पुनरावर्ती नियम में \(n^2\) हर चरण बदलता है।