यदि \(a_1=3\), \(a_2=4\) और \(a_n=a_{n-1}+a_{n-2}+2n\) है तो \(a_3\) क्या होगा?

If \(a_1=3\), \(a_2=4\), and \(a_n=a_{n-1}+a_{n-2}+2n\), what is \(a_3\)?

Author: Muft Shiksha Editorial Team Published:
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Correct Answer

B. (13)

Step 1

Concept

\(a_3=4+3+2\times3=13\). Exam tip: add current (2n) with the previous two terms.

Step 2

Why this answer is correct

The correct answer is B. (13). \(a_3=4+3+2\times3=13\). Exam tip: add current (2n) with the previous two terms.

Step 3

Exam Tip

\(a_3=4+3+2\times3=13\) है। पिछले दो पदों के साथ वर्तमान (2n) जोड़ें।

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FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(a_1=3\), \(a_2=4\) और \(a_n=a_{n-1}+a_{n-2}+2n\) है तो \(a_3\) क्या होगा? / If \(a_1=3\), \(a_2=4\), and \(a_n=a_{n-1}+a_{n-2}+2n\), what is \(a_3\)?

Correct Answer: B. (13). Explanation: \(a_3=4+3+2\times3=13\) है। पिछले दो पदों के साथ वर्तमान (2n) जोड़ें। / \(a_3=4+3+2\times3=13\). Exam tip: add current (2n) with the previous two terms.

Which concept should I revise for this Mathematics MCQ?

\(a_3=4+3+2\times3=13\). Exam tip: add current (2n) with the previous two terms.

What exam hint can help solve this Mathematics question?

\(a_3=4+3+2\times3=13\) है। पिछले दो पदों के साथ वर्तमान (2n) जोड़ें।