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How many terms of the geometric progression (5,15,45,\ldots) have sum (1820)?गुणोत्तर श्रेणी (5,15,45,\ldots) में कितने पदों तक योग (1820) होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (6)(6)
(S_n=\frac{5(3^n-1)}{3-1}), and (\frac{5(3^n-1)}{2}=1820) gives (3^n=729), so (n=6). In exams, simplify the sum and identify the power.(S_n=\frac{5(3^n-1)}{3-1}) और (\frac{5(3^n-1)}{2}=1820) से (3^n=729), इसलिए (n=6) है। परीक्षा में योग को सरल करके घात पहचानें।
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