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For which of the following expressions does taking out a common factor first leave a difference of squares?
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Answer and explanation
Correct answer: \(x^3-4x\)
In \(x^3-4x\), take out the common factor \(x\): \(x(x^2-4)\). Now \(x^2-4=x^2-2^2\), a difference of squares. In \(x^3+4x\), the remaining expression is a sum. Exam tip: check the HCF first.
Frequently asked questions
What is the correct answer to this question?
\(x^3-4x\)
Why is this the correct answer?
In \(x^3-4x\), take out the common factor \(x\): \(x(x^2-4)\). Now \(x^2-4=x^2-2^2\), a difference of squares. In \(x^3+4x\), the remaining expression is a sum. Exam tip: check the HCF first.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Factorisation.
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