Factorise (5xy-10x+3y-6) by grouping.
Answer and explanation
Correct answer: \((5x+3)(y-2)\)
Group the expression as \((5xy-10x)+(3y-6)\). This gives \(5x(y-2)+3(y-2)\). Taking the common binomial \((y-2)\) gives \((5x+3)(y-2)\). On expansion, option B gives incorrect signs for the \(x\)- and \(y\)-terms. Exam tip: expand your final factors once to check the signs of the middle and constant terms.
Frequently asked questions
What is the correct answer to this question?
\((5x+3)(y-2)\)
Why is this the correct answer?
Group the expression as \((5xy-10x)+(3y-6)\). This gives \(5x(y-2)+3(y-2)\). Taking the common binomial \((y-2)\) gives \((5x+3)(y-2)\). On expansion, option B gives incorrect signs for the \(x\)- and \(y\)-terms. Exam tip: expand your final factors once to check the signs of the middle and constant terms.
Which subject and chapter does this question cover?
This is a Class 9 Mathematics question. Chapter: Exploring Algebraic Identities. Topic: Factorisation.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
